The velocity was positive and constant for the first part of the graph. From 3 - 6 seconds the velocity was 0, followed by a negative velocity for 1 s, and then 0 velocity.
The acceleration for this graph was 0.
The second graph is also a time vs. distance graph. The motion can be described as start at 3 m from the motion detector. Walk away for 2 s. Stay for a second. Walk away for a second. Present position=1.5 m. Stay at 1.5 m for 2 s. Then walk back to 3 m for 3 seconds.
The velocity is positive for the first 3 seconds. Then velocity becomes 0 because there is not movement. For 1 second again there is a positive velocity followed by a zero velocity. For the last 3 seconds there is a negative velocity because there is movement away from the origin and opposing the original direction of movement.
There is no acceleration in this graph.
Our third graph was time vs velocity. The initial speed was 0m/s for 2 seconds. During seconds 2 - 5 the speed becomes 0.5m/s. The speed goes back to being 0 m/s for another 2 seconds. The speed for the last 3 seconds reverses direction and becomes 0.5m/s (in the opposite direction of the initial speed.)
The distance vs. time graph version of the graph above would have a line on the x-axis for the first 2 seconds, followed by a positive slope for the next 3 seconds, that reaches from 0 to 1.5. There would be a line at 1.5 parallel to the x-axis for 3 seconds, and then a line that has a negative slope and reaches from 1.5m on second 7 to 0 m on second 10.
The acceleration graph would have a 0 slope, and can be graphed on the x-axis.
Graph number four shows velocity vs. time. The velocity starts off as 0 and accelerates in a positive direction for four seconds, until it reaches 0.5 m/s.The velocity stays at 0.5 m/s for 2 seconds. At 6 seconds, the velocity drops down to -0.4m/s and remains like that until the 9th second, when the movement stops, and velocity is 0.
The distance reached from the origin of the graph in the first 6 seconds is 2m. Then over the next 3 seconds the distance decreases by 1.5 m and the position is 0.5 m. The distance remains 0.5 m for the last second.
The acceleration for the first 4 seconds of the graph is 0.125m/s. It is positive. There is no acceleration for the rest of the graph.
The fifth graph is a position vs. time graph. The position starts at 0.8m and over the first 3 seconds the position increases steadily going up to 1.8 m. The distance remains 1.8 m for about 4 seconds. After 4 seconds, it increases steadily up to 2.5 m over a 1 s. time period.
The velocity for this graph starts off as positive at about 0.3 m/s for about 3 seconds. Then the velocity remains 0 for four seconds. This means there is no movement. The velocity becomes 0.5m/s for the last second.
The acceleration for the whole graph is 0. There is no increase or decrease in speed.
The graph above shows a velocity vs. time relationship. At first the velocity is less than 0.5 m/s. This lasts for about 3 seconds. Then the velocity becomes a little over -0.5m/s. The velocity stays at this rate for about 4 seconds. Then at 7 seconds, the velocity becomes 0m/s.
First there is a movement of 1.5 m in 3 seconds. This is followed by another movement of 2 m over 4 seconds, in a contrary direction. After the initial 7 seconds, there is a plateau in distance and no movement for 3 seconds.
There is no acceleration in the above graph at an part.
No comments:
Post a Comment